Asked by Keli
Lead ii nitrate was added to a small test tube as well as Sodium hydroxide. What is the equilibrium equation for the reaction of lead ii ions and hydroxide ions?
Answers
Answered by
DrBob222
The small ii s should be II.
and in parentheses as (II).
Pb^+2 + 2OH^- ==> Pb(OH)2(s).
If excess OH^- is added, the Pb(OH)2(s) dissolves to form a complex ion.
Pb(OH)2(s) + 2OH^- ==> Pb(OH)<sub>4</sub><sup>-2</sup>
and in parentheses as (II).
Pb^+2 + 2OH^- ==> Pb(OH)2(s).
If excess OH^- is added, the Pb(OH)2(s) dissolves to form a complex ion.
Pb(OH)2(s) + 2OH^- ==> Pb(OH)<sub>4</sub><sup>-2</sup>
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.