Lead ii nitrate was added to a small test tube as well as Sodium hydroxide. What is the equilibrium equation for the reaction of lead ii ions and hydroxide ions?

Answer 1

The small ii s should be II.
and in parentheses as (II).
Pb^+2 + 2OH^- ==> Pb(OH)2(s).
If excess OH^- is added, the Pb(OH)2(s) dissolves to form a complex ion.
Pb(OH)2(s) + 2OH^- ==> Pb(OH)₄^-2