Knowing the given conditions, write the equation of the circle. Center at (4,2) and the circle passes through (-1,-1).

Please help!

2 answers

I will assume you know that the equation of a circle with centre (h,k) and radius r is
(x-h)^2 + (y-k)^2 = r^2

then (x-4)^2 + (y-2)^2 = r^2
but (-1,-1) lies on it, so
(-1-4)^2 + (-1-2)^2 = r^2
r^2 = 34

(x-4)^2 + (y-2)^2 = 34
Thanks!
Similar Questions
  1. Write the equation for the circle with center at (- 8, - 6) and radius of 10.(x+8)² + (y + 6)² = 10 (x+8)² + (y + 6)² = 100
    1. answers icon 3 answers
  2. The diameter of a circle has endpoints P(–10, –2) and Q(4, 6).a.Find the center of the circle. b.Find the radius. If your
    1. answers icon 12 answers
  3. A diameter of a circle has endpoints P(–10, –2) and Q(4, 6).Find the center of the circle. Find the radius. If your answer
    1. answers icon 1 answer
  4. Examine the diagram, where AB←→and CD←→ are secants to the circle, and they intersect inside of the circle at point P,
    1. answers icon 1 answer
more similar questions