Ask a New Question

Knowing the given conditions, write the equation of the circle. Center at (5,3) and tangent to the y-axis.

1 answer

The radius must be R = 5, because the center is located along the x=5 line.

(x-5)^2 + (y-3)^2 = R^2 = 25

is your equation.

Ask a New Question or answer this question.

Similar Questions

standard equation of circle concentric with X^2+Y^2-2X-8Y+1=0 and tangent to line 2X-Y=3Complete the squares to find the center
1. 1 answer
Line segment AB is tangent to circle O at B. The diagram is not drawn to scale.The figure is a circle O with a triangle A B O
1. 1 answer
Tangent Lines practice problems. Unit 73. In the figure below, lines that appear to be tangent are tangent. Point O is the
1. 11 answers
Find an equation of the circleCenter on line y–4=0, tangent x-axis at (–2, 0)
1. 1 answer

more similar questions