a)
600=6A^2
600/6=(6A^2)/6
100=A^2
√100=√(A^2)
10=A
b)
1350=6A^2
1350/6=(6A^2)/6
1225=A^2
√225=√(A^2)
15=A
c)
2400=6A^2
2400/6=(6A^2)/6
400=A^2
√400=√(A^2)
20=A
is my answer for a,b and c correct?
Kirkor has to design and build a box with the greatest volume possible. the box is a rectangular prism. for each surface area, what will be the dimensions of the box?
a) 600 square inches
b) 1350 cm^2
c) 2400 square inches
3 answers
The greatest volume is obtained if the box is a cube
let each side length be x
Each side will have a surface area of x^2 and there are 6 such sides
a) 6x^2 = 600
x^2 = 100
x = 10
the box will be 10 by 10 by 10
Do the other two in the same way
let each side length be x
Each side will have a surface area of x^2 and there are 6 such sides
a) 6x^2 = 600
x^2 = 100
x = 10
the box will be 10 by 10 by 10
Do the other two in the same way
b)
1350=6A^2
1350/6=(6A^2)/6
1225=A^2
√225=√(A^2)
15=A
c)
2400=6A^2
2400/6=(6A^2)/6
400=A^2
√400=√(A^2)
20=A
1350=6A^2
1350/6=(6A^2)/6
1225=A^2
√225=√(A^2)
15=A
c)
2400=6A^2
2400/6=(6A^2)/6
400=A^2
√400=√(A^2)
20=A