Keep going. You’re trying to get m alone on one side of the equation, and a constant alone on the other side of the equation. We can start by making sure that all the m terms are only on one side of the equation. What move can you make to get rid of the 6m on the right side of the equation, while keeping the equation balanced?

2
3

(7+3m)
=
3+3m

2 ·
2
3

(7+3m)
=
2 · (3+3m)

3(7+3m)
=
6 + 6m

21 + 9m
=
6 + 6m

Subtract 6m from both sides

Add 6m to both sides

Multiply both sides by 6m

Divide both sides by 6m

1 answer

You're on the right track with isolating \( m \). To eliminate the \( 6m \) on the right side of the equation while maintaining balance, you should subtract \( 6m \) from both sides.

Here's how to do it following your equation:

Starting from: \[ 21 + 9m = 6 + 6m \]

You would subtract \( 6m \) from both sides: \[ 21 + 9m - 6m = 6 + 6m - 6m \]

This simplifies to: \[ 21 + 3m = 6 \]

Now you have all the \( m \) terms on one side of the equation. You can proceed to isolate \( m \) further by removing the constant on the left side. Would you like to move on to the next step?