Keep going. We’re trying to get b alone on one side and a constant alone on the other. We can make a balanced move so that the b terms are only on one side. We have −2b+9 on the left. What move can we make to get rid of −2b on the left, so that all the b terms are on the right, while maintaining balance?

13−2(b+2)
=
6b−7

13−2b−4
=
6b−7

−2b+9
=
6b−7

Add 2b to both sides

Subtract 2b from both sides

Divide both sides by 2b

Multiply both sides by 2b

1 answer

To isolate \(b\) on one side of the equation, you want to eliminate the \(-2b\) term from the left side. This can be accomplished by adding \(2b\) to both sides of the equation.

Starting from your equation:

\[ -2b + 9 = 6b - 7 \]

If you add \(2b\) to both sides, you'll have:

\[ -2b + 2b + 9 = 6b + 2b - 7 \]

This simplifies to:

\[ 9 = 8b - 7 \]

So, the correct move is:

Add 2b to both sides.

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