To isolate \( \frac{41}{4}s \) on the right side of the equation \( 8 = \frac{41}{4}s + 10 \), you should follow these steps to eliminate the 10 on the right side while maintaining the balance of the equation:
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Subtract 10 from both sides:
\[ 8 - 10 = \frac{41}{4}s + 10 - 10 \]
This simplifies to:
\[ -2 = \frac{41}{4}s \]
Now, you have \( \frac{41}{4}s \) alone on the right side. If your goal is to solve for \( s \), you can divide both sides by \( \frac{41}{4} \).
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Multiply both sides by the reciprocal of \( \frac{41}{4} \) (which is \( \frac{4}{41} \)):
\[ s = -2 \cdot \frac{4}{41} \]
This gives:
\[ s = -\frac{8}{41} \]
So \( s \) is isolated and equals \( -\frac{8}{41} \).