(HI) = 16.7/10 = 1.67 M
.....H2 + I2 ==> 2HI
I.....0....0......1.67
C.....x....x......-2x
E.....x....x.....1.67-2x
Plug the E line into the Kc expression and solve for x
Kc = 28 at some temperature for the reaction
H2(g) + I2(g) ⇀↽ 2 HI(g).
If 16.7 moles of HI are introduced into a
10.0 liter vessel, how many moles of I2 are
present at equilibrium?
Answer in units of mol.
1 answer