K, Q1.A sphere of radius 5cm is lowered into a rectangular tank 50cm long and 20cm wide containing water to a depth of 10cm.The sphere floats with half of its surface above the level of the surface of the water

Question

K, Q1.A sphere of radius 5cm is lowered into a rectangular tank 50cm long and 20cm wide containing water to a depth of 10cm.The sphere floats with half of its surface above the level of the surface of the water 
Calculate (a)the volume of the sphere, (b)the volume of water in the tank (cccc)the surface area of the sphere above the water.=

Steve · Answer

sphere: v = 4/3 pi r^3 = 500pi/3 = 524 cm^3 The diameter of the sphere is equal to the depth of the water, so it will be completely submerged as the water level rises.