(k+3)^2=(2k-1)^2=0

Question

Please help me solve this equation or maybe one like it......I keep doing it wrong.

6p^2(p+1)=4(p+1)-5p(p+1)

I also keep doing this problem wrong. I have the answer but I don't understand how its done. Please help!!

Answer 1

Hint.
Each term on both sides has a factor (p+1). Divide all terms on both sides by (p+1). This will simplify it for you.

Answer 2

Also, because of the (p+1) term remember that p=-1 will be a solution.

Answer 3

Okay...

Now I got 6p^2=4-5p(p+1)

I got it now....Thanks!!

the answer is (-4/3,-1,1/2)

Answer 4

What about the first question??? Please help me with that one...

Answer 5

I don't think you copied the first question correctly. Did you intend 2 equal signs?

Answer 6

I copied it wrong....

(k+3)^2=(2k-1)^2 .....Is the problem.

Answer 7

square both sides, collect like terms and solve.
Here's the first step:
(k+3)^2 = (2k-1)^2
k^2 + 6k + 9 = 4k^2 - 4k + 1

Combine all the like terms. You might factor it out, but I would suggest using the quadratic equation.