Judy walks a certain distance due north, then walks twice as far due west. At the end of her trip, the straight-line distance from her starting point to her final position is 112m.

Question

Judy walks a certain distance due north, then walks twice as far due west.  At the end of her trip, the straight-line distance from her starting point to her final position is 112m. 
a) What is the length of each leg of the trip?
 b) What is the direction of her total displacement relative to north?

Please help ASAP

Steve · Answer

x^2 + (2x)^2 = 112 The angle θ West of North is tanθ = 2/1

Anonymous · Answer

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