The first two hours are free, so Juanita will be charging for a total of 4 hours of work. The cost of those 4 hours will be 4 times $60, or $240. She also charges a $125 home-visit fee, so the total cost will be $240 + $125, or $365. Therefore, the correct equation is:
B) c=125+60(6)
Juanita is an HVAC repair person. She charges a $125 home-visit fee and $60 per hour, with the first two hours free. Which equation could Janice use to calculate the cost, c, to have Juanita work at her house for 6 hours?
A) c=125+60(6−2)
B) c=125+60(6)
C) c=125+60(6+2)
D) c=(125+60)(6−2)
5 answers
no,
the choice you made does not produce the answer you actually worked out
the choice you made does not produce the answer you actually worked out
You are correct, I apologize for that mistake. I made an error in my calculation. The correct answer is:
C) c=125+60(6+2)
To get 6 hours of work, we need to consider the first two hours as free. That leaves a total of 4 hours of chargeable work. So the equation becomes:
c = 125 + 60(4)
Simplifying this gives:
c = 125 + 240
c = 365
Therefore, the total cost for Juanita to work at Janice’s house for 6 hours would be $365.
C) c=125+60(6+2)
To get 6 hours of work, we need to consider the first two hours as free. That leaves a total of 4 hours of chargeable work. So the equation becomes:
c = 125 + 60(4)
Simplifying this gives:
c = 125 + 240
c = 365
Therefore, the total cost for Juanita to work at Janice’s house for 6 hours would be $365.
Wrong again, I hope you are not guessing.
besides , again your work does not correspond to the choice of answers
you made, furthermore, it is different from your first wrong answer.
besides , again your work does not correspond to the choice of answers
you made, furthermore, it is different from your first wrong answer.
I apologize for the confusion. You are correct that my previous answers were incorrect. The correct equation to calculate the cost, c, to have Juanita work at Janice's house for 6 hours is:
c = 125 + 60(6-2)
This is because the first two hours are free, and the remaining 4 hours are charged at a rate of $60 per hour. Solving this equation gives:
c = 125 + 60(4)
c = 365
Therefore, the cost to have Juanita work at Janice's house for 6 hours is $365. Again, I apologize for the previous errors.
c = 125 + 60(6-2)
This is because the first two hours are free, and the remaining 4 hours are charged at a rate of $60 per hour. Solving this equation gives:
c = 125 + 60(4)
c = 365
Therefore, the cost to have Juanita work at Janice's house for 6 hours is $365. Again, I apologize for the previous errors.
1 answer