Let's denote Joelle's number of rocks as J and Lewis's number of rocks as L. We can set up the following system of equations:
J = 18 + 4w (J is the number of rocks Joelle has after w weeks)
L = 30 + 3w (L is the number of rocks Lewis has after w weeks)
To find the week when the number of rocks in their collections is equal, we can set J = L and solve the system of equations:
18 + 4w = 30 + 3w
Now, we can solve for w to find the week when the number of rocks in their collections is equal.
Joelle currently has 18 rocks in her collection and gains 4 each week. Lewis currently has 30 rocks in his collection and gains 3 each week. Set up a system of equations to show how many rocks each has in their collection.
how many rocks will Joelle and lewis have when the amount of rocks in their collections is equal
3 answers
okay solve then
18 + 4w = 30 + 3w
To solve for w, we want to isolate the w term on one side of the equation. Let's subtract 3w from both sides:
18 + 4w - 3w = 30 + 3w - 3w
Simplifying:
w = 12
Therefore, after 12 weeks, the number of rocks in Joelle and Lewis's collections will be equal. To find the number of rocks at that time, we can substitute w = 12 into either equation:
J = 18 + 4(12) = 18 + 48 = 66 rocks
L = 30 + 3(12) = 30 + 36 = 66 rocks
So, after 12 weeks, Joelle and Lewis will each have 66 rocks in their collections.
To solve for w, we want to isolate the w term on one side of the equation. Let's subtract 3w from both sides:
18 + 4w - 3w = 30 + 3w - 3w
Simplifying:
w = 12
Therefore, after 12 weeks, the number of rocks in Joelle and Lewis's collections will be equal. To find the number of rocks at that time, we can substitute w = 12 into either equation:
J = 18 + 4(12) = 18 + 48 = 66 rocks
L = 30 + 3(12) = 30 + 36 = 66 rocks
So, after 12 weeks, Joelle and Lewis will each have 66 rocks in their collections.
1 answer