Joe wishes to hang a sign weighing 730 N so that cable A, attached to the store, makes a 30.0° angle, as shown below. Cable B is horizontal and attached to an adjoining building. What is the tension in cable B?

Answer 1

T sin 30 = force up = 730
T = 1460 N in cable A
T cos 30 = horizontal component = 1460 cos 30 = 1264 N

Answer 2

thank you and the answer is 433 to anyone else trying to figure this out

Answer 3

The answer is 375 N