JK, KL, and LJ are all tangent to circle O. The diagram is not drawn to scale. If JA = 12, AL = 15, and CK = 5, what is the perimeter of ΔJKL? (1 point) Responses 34 34 64 64 32 32 54

Answer 1

To find the perimeter of triangle JKL, we need to find the lengths of JK, KL, and LJ.

Since JK, KL, and LJ are all tangent to circle O, we know that JK is equal to JA, KL is equal to AL, and LJ is equal to CK. Therefore, JK = 12, KL = 15, and LJ = 5.

The perimeter of triangle JKL is the sum of the lengths of its sides: JK + KL + LJ = 12 + 15 + 5 = 32.

So, the perimeter of triangle JKL is 32.

Therefore, the correct answer is:

32