Asked by Rosie
Jason approaches a rotary in her 3,500kg Mercedes. Its radius of curvature 95m but his speed is 25m/s. The acceleration is 6.6 m/s^2. What is the coefficient friction between his tires and the road?
I know Mu mg=mv^2/R but I am unable to complete my equation and continue to end up with a negative number
I know Mu mg=mv^2/R but I am unable to complete my equation and continue to end up with a negative number
Answers
Answered by
bobpursley
Netative number?
mu=v^2/(Rg) R=95, g= 9.8, v^2=positive.
How are you getting a negative number? mu is defined as friction force divided by force normal. don't use -9.8m/s^2 times mass as force normal. Forces have directions, that can change - to +
mu=v^2/(Rg) R=95, g= 9.8, v^2=positive.
How are you getting a negative number? mu is defined as friction force divided by force normal. don't use -9.8m/s^2 times mass as force normal. Forces have directions, that can change - to +
Answered by
Rosie
ok I think I figured it out mu=0.67
Answered by
Rosie
thank you for your help
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.