Asked by Oti
lim √x lnx as x approaches 0 positive
Answers
Answered by
oobleck
using l'Hospital's Rule,
√x lnx = lnx/(1/√x)
so the limit is
(1/x) / (-1/2 * x^-(3/2) = -2√x → 0
√x lnx = lnx/(1/√x)
so the limit is
(1/x) / (-1/2 * x^-(3/2) = -2√x → 0
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