it takes a maximum force of 460 N to move a 125 kg crate. What is the coefficient of the maximum static friction between the crate and the floor?

Answer 1

Wc = mg = 125kg * 9.8N/kg = 1225N =
Weight of crate.

Fc = 1225N @ 0deg.
Fp = 1225sin(0) = 0 = Force parallel to the floor = Hor comp.
Fv = 1225cos(0) = 1225N. = Force perpendicular to the floor.

Fn = Fap - Fp - Fs = 0,
460 - 0 - u*Fv = 0,
u*Fv = 460,
u = 460 / Fv = 460 / 1225 = 0.376 =
coefficient of static friction.