It looks like you're analyzing a situation involving a crate being subjected to applied and frictional forces. Let's break down your questions.
-
Does the crate start to move?
- No.
-
What is the horizontal net force on the crate?
- 0 N (since the applied force is balanced by the frictional force).
-
Are the forces on the crate balanced?
- Yes.
-
What happened to the friction force as you increased the applied force from 50N to 150N?
- Nothing (the friction force remains equal to the applied force as long as it doesn’t exceed the maximum static frictional force).
-
What type of friction is this?
- This is static friction, as the crate is not moving and the applied force has not exceeded the maximum static friction force.
-
What is the maximum force you can apply to the crate just before it starts to move?
- The maximum force that can be applied just before the crate moves is equal to the maximum static friction force. This value is not provided in your scenario, but you would need to know the coefficient of static friction and the normal force acting on the crate to calculate it. The formula is: \[ F_{\text{max static friction}} = \mu_s \cdot N \] where \( \mu_s \) is the coefficient of static friction and \( N \) is the normal force acting on the crate.
If you have the coefficient of static friction and the normal force, you can calculate that maximum force.
1 answer