Asked by Fred
It takes a force of 22 N to push a 10 kg box horizontally with a constant velocity over concrete. What is the coefficient of kinetic friction between the box and the concrete?
My guess is 10 kg/22 N = 0.4545 but I'm not sure if you have to take in account vertical forces or if 0.4545 represents the static frictional force.
My guess is 10 kg/22 N = 0.4545 but I'm not sure if you have to take in account vertical forces or if 0.4545 represents the static frictional force.
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