The key here is "isosceles". That means the legs are equal.
7y-4 = 8y-18
y = 14
Isosceles trapezoid ABCD has legs AB and CD and base BC If AB = 7y – 4, BC = 4y – 6, and CD = 8y – 18, find the value of y.
6 answers
ummm......... is this right?
Its right
but what about the other one 4y-6? yall only be doing the sides and it wants y but you left out the base
We are told that the legs of the isosceles trapezoid are AB and CD
AB = 7y - 4
CD = 8y - 18
In any isosceles trapezoid, the two legs are of
equal length. Therefore, AB = CD
7y - 4 = 8y - 18
Add 18 to both sides of the equation 7y - 4 + 18 = 8y - 18 + 18
7y + 14 = 8y
Subtract 7y from both sides of the equation
7y - 7y + 14 = 8y - 7y 14 = y
⇒y=14
Lmk if anything is wrong or nah
AB = 7y - 4
CD = 8y - 18
In any isosceles trapezoid, the two legs are of
equal length. Therefore, AB = CD
7y - 4 = 8y - 18
Add 18 to both sides of the equation 7y - 4 + 18 = 8y - 18 + 18
7y + 14 = 8y
Subtract 7y from both sides of the equation
7y - 7y + 14 = 8y - 7y 14 = y
⇒y=14
Lmk if anything is wrong or nah
You right fam thank you sm