Is there any method to calculate the value of (1+i)^n + (1-i)^n , without using the binomial theorem or Euler formulation?

As (1-i) is the conjugate of (1+i) we can take the value of (1+i)+(1-i)= real part of (1+i)

But how to avoid Euler formula?

1 answer

n is a positive integer.
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