Asked by Ashley
Is the set of all real numbers x such that 0 < x ≤ 1, with operation multiplication.
So I choose any elements x,y in the above set and considered their multiplication.
Since x and y are two different elements can their product be equal to 1? (Since if x = 1 then y cannot be equal to 1 right?)
So can we say the closure property holds for above set?
Thanks!
So I choose any elements x,y in the above set and considered their multiplication.
Since x and y are two different elements can their product be equal to 1? (Since if x = 1 then y cannot be equal to 1 right?)
So can we say the closure property holds for above set?
Thanks!
Answers
Answered by
oobleck
closure holds, but why do you say that x≠y? That is not necessary.
Answered by
Ashley
Isn't it required to show the closure property holds for two different number x,y?
Answered by
oobleck
closure means that if x and y are elements of the set, then x*y is also.
They need not be different.
They need not be different.
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