check to see whether
f(-x) = f(x). If so, it is even
So, check
1/(-x-1) = 1/(x-1)
it is clearly not even.
So, now check to see if it's odd: f(-x) = -f(x)
have at it.
Is the following function odd, even, or neither? Give reasons for your answer.
f(x) = 1/(x-1)
The textbook answer section explains that it is neither. I assumed it would be odd because the power of x is 1 which is odd.
4 answers
f(x) = 1/(x-1)
it blows up when x = 1
a function f is even if f (-x) = f (x)
a function is odd if f (-x) = -f (x)
now try x = 2
f(-2) = f(2)???
1/(-2-1) = 1/(2-1)
1/-3 = 1/1 No, I think not odd then
but now
f(-2) = -f(2) ????
1/1 = - 1/1 No ! , Not even either
it blows up when x = 1
a function f is even if f (-x) = f (x)
a function is odd if f (-x) = -f (x)
now try x = 2
f(-2) = f(2)???
1/(-2-1) = 1/(2-1)
1/-3 = 1/1 No, I think not odd then
but now
f(-2) = -f(2) ????
1/1 = - 1/1 No ! , Not even either
I have another question.
if a function has a larger exponent how does it affect its graph?
for example, if x^3 and x^6 are graphed. How can match each function to their graph.
if a function has a larger exponent how does it affect its graph?
for example, if x^3 and x^6 are graphed. How can match each function to their graph.
The highest power affects the graph.
odd powers go off to infinity in both directions because odd powers of negative numbers are negative
even powers look more like parabolas, maybe with wiggles near the vertex, but since even powers are always positive, they go up on both ends.
odd powers go off to infinity in both directions because odd powers of negative numbers are negative
even powers look more like parabolas, maybe with wiggles near the vertex, but since even powers are always positive, they go up on both ends.