Is (–5, 0.5) a solution of this system?

x – 4y = –7,

0.2x + 2y = 0

Substitute (–5, 0.5) into x – 4y = –7 to get
.
Substitute (–5, 0.5) into 0.2x + 2y = 0 to get
.
Simplify the above equations to get

1 answer

To determine if \((-5, 0.5)\) is a solution of the given system of equations, we will substitute \(x = -5\) and \(y = 0.5\) into each equation.

First Equation:

\[ x - 4y = -7 \]

Substituting \((-5, 0.5)\): \[ -5 - 4(0.5) = -7 \] Calculating: \[ -5 - 2 = -7 \] This simplifies to: \[ -7 = -7 \quad \text{(True)} \]

Second Equation:

\[ 0.2x + 2y = 0 \]

Substituting \((-5, 0.5)\): \[ 0.2(-5) + 2(0.5) = 0 \] Calculating: \[ -1 + 1 = 0 \] This simplifies to: \[ 0 = 0 \quad \text{(True)} \]

Conclusion:

Both equations are satisfied, therefore \((-5, 0.5)\) is a solution of the system.