Asked by lexi
A solution of 118 mL of 0.160 M KOH is mixed with a solution of 240 mL of 0.230 M NiSO4.
How many grams of this precipitate (Ni(OH)2) form?
I have the balanced equation as 2KOH (aq)+ NiSO4 (aq) ----> K2SO4 (aq) + Ni(OH)2
I don't need the answer but I would really like to know how to do it.
How many grams of this precipitate (Ni(OH)2) form?
I have the balanced equation as 2KOH (aq)+ NiSO4 (aq) ----> K2SO4 (aq) + Ni(OH)2
I don't need the answer but I would really like to know how to do it.
Answers
Answered by
oobleck
118mL of 0.16M gives 0.118 * 0.16 = 0.01888 moles of KOH
Now the equation tells you how many moles of Ni(OH)2 you will get
convert that to grams.
Now the equation tells you how many moles of Ni(OH)2 you will get
convert that to grams.
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