Yes, it is.
To check, we substitute x = -2 and y = 6 into both equations and see if both equations are true:
x + 2y = 10
-2 + 2(6) = 10
10 = 10 (this is true)
3x + y = 0
3(-2) + 6 = 0
0 = 0 (this is also true)
Since both equations are true when x = -2 and y = 6, (−2, 6) is a solution to the system of the linear equations.
Is (−2, 6) a solution to the system of these linear equations: x+2y=10 and 3x+y=0? Why?(1 point)
1 answer