is (-2,6) a solution to the system of these linear equations: x+2y=10 and 3x+y=0

Answer 1

To determine if the point (-2, 6) is a solution to the system of linear equations, we need to substitute the values of x = -2 and y = 6 into both equations and see if they hold true.

For the first equation x + 2y = 10:
-2 + 2(6) = -2 + 12 = 10
Thus, the first equation holds true for the point (-2, 6).

For the second equation 3x + y = 0:
3(-2) + 6 = -6 + 6 = 0
Thus, the second equation also holds true for the point (-2, 6).

Since both equations hold true for the point (-2, 6), (-2, 6) is indeed a solution to the system of linear equations.