And why didn't you write what you know? I assume those are SOLUTIONS of ferric nitrate and sodium carbonate.
Iron (III) Nitrate reacts with sodium carbonate to form a precipitate.
The molecular equation is as follows: I assume you have that.
Fe(NO3)3(aq) + Na2CO3(aq) ==> Fe2(CO3)3(s) + NaNO3(aq). Balance that.
2Fe(NO3)3(aq) + 3Na2CO3(aq) ==> Fe2(CO3)3(s) + 6NaNO3(aq).
That is the total balanced equation. Now turn that into the total ionic equation.
2Fe^3+(aq) + 6(NO3)-(aq) + 6Na^+ + 3(CO3)^2-(aq) ==> Fe2(CO3)3(s) + 6Na^+ + 6(NO3)^-(aq).
To turn this into the net ionic equation, cancel those ions common to both sides of the equation. Those are Na^+ and (NO3)^-. The net ionic equation is what is left. That is.
2Fe^3+(aq)+ + 3(CO3)^2-(aq) ==> Fe2(CO3)3(s)
Iron (III) Nitrate reacts with sodium carbonate to form a precipitate.
Be sure to indicate oxidation states and the precipitate.
Skeletal Equation:
Ionic Equation:
NET Ionic Equation:
Balanced Equation:
Spectator Ions:
I got the skeletal equation, but I need help with the Ionic Equation and the NET Ionic Equation. Please help!!
3 answers
Thank you!!
How do we write the spectator ions then?