iron cube of side 10 cm is kept on a horizontal table . If the density of iron cube is 8000 kg /m cube , find the pressure on the portion of the table where the cube is kept?

Answer 1

weight= mg=8000kg/m^3 * (.1m)^3

pressure= force/area=mg/(.1)^2=
= 8000kg*9.8N/kg*.1 N/m^2