Asked by Deborah
Find the mass of a cylindrical iron pipe 2.1m long and 12cm in external diameter, if the metal is 1cm thick and of density 7.8g/cm cube. Take π=22/7
Answers
Answered by
oobleck
impatient much?
the volume of a cylinder is base area * length
you have a circular base, but with a hole in it. Such a ring of inner radius r and outer radius R has area
a = π(R^2-r^2)
So, your pipe has an outer radius R=6cm and an inner radius r=5cm
That makes the volume of metal
π(6^2-5^2) * 210 cm^3
and, as you know, mass = density * volume
= 7.8 * π(6^2-5^2) * 210 = _______ grams
the volume of a cylinder is base area * length
you have a circular base, but with a hole in it. Such a ring of inner radius r and outer radius R has area
a = π(R^2-r^2)
So, your pipe has an outer radius R=6cm and an inner radius r=5cm
That makes the volume of metal
π(6^2-5^2) * 210 cm^3
and, as you know, mass = density * volume
= 7.8 * π(6^2-5^2) * 210 = _______ grams
Answered by
Anonymous
I don't get were is my answers to my question
Answered by
Faith
How did u get 210cm^3
Answered by
Faith
Where is my answer
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