4. speed of ball at 2 sec. The horizontal speed is same, v(t)=vi-g(r), then compute the speed from those two components.
5. At the top, PE = initial KE in vertical
mgh=1/2 m vi'^2 where vi is initial vertical velocity, solve for h.
Initial Statement: A soccer ball is kicked with an initial horizontal velocity of 15 m/s and an initial vertical velocity of 14 m/s.
1) What is the initial speed of the ball?
20.518
2) What is the initial angle θθ of the ball with respect to the ground?
43.025
3) What is the maximum height the ball goes above the ground?
10
4) How far from where it was kicked will the ball land?
42.860
5) What is the speed of the ball 2.2 seconds after it was kicked?
6) How high above the ground is the ball 2.2 seconds after it is kicked?
I've gotten through the first four parts of this problem, but I've gotten stuck on five and six, I think that I need to figure out the time that the ball is at maximum height, which I found was 2.094 seconds, and then use that to find vertical velocity, but everything that I've tried has resulted in a wrong answer.
1 answer
1 answer