Question
A soccer ball is kicked with an initial horizontal velocity of 19.0 m/s and an initial vertical velocity of 14.0 m/s
6) How high above the ground is the ball 1.1 seconds after it is kicked?
6) How high above the ground is the ball 1.1 seconds after it is kicked?
Answers
h(t) = 14.0t - 4.9t^2
h(1.1) = 9.47m
h(1.1) = 9.47m
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