In which of the given sets of numbers are all the numbers solutions of 9−2x≥3?(1 point)

Question

3, 4, 5, 6

0, 1, 2, 3

4, 5, 6

0, 1, 3, 5

Answer 1

First, we need to solve the inequality 9 - 2x ≥ 3 for x.

Subtract 9 from both sides:

-2x ≥ -6

Divide both sides by -2 (and remember to reverse the inequality sign since we are dividing by a negative number):

x ≤ 3

Now, let's check which of the given sets of numbers are all solutions of x ≤ 3.

Option 1: 3, 4, 5, 6 - No, this set contains numbers greater than 3.

Option 2: 0, 1, 2, 3 - Yes, all of these numbers are less than or equal to 3.

Option 3: 4, 5, 6 - No, this set contains only numbers greater than 3.

Option 4: 0, 1, 3, 5 - No, this set contains a number (5) greater than 3.

So, the correct set is {0, 1, 2, 3}.