In which of the given sets of numbers are all the numbers solutions of 4x+7≠23? (1 point)

Question

Responses

A: 1, 2, 3, 4

B: 3, 4, 6, 7

C: 2, 3, 5, 6

D: 4, 5, 6, 7

Answer 1

First, we need to find the value of x that makes the equation true:

4x + 7 ≠ 23

Subtract 7 from both sides:

4x ≠ 16

Divide by 4:

x ≠ 4

Now we know that x cannot equal 4. Let's check each set of numbers to see which one does not include 4 as a solution:

A: 1, 2, 3, 4 (includes 4, so not a solution)
B: 3, 4, 6, 7 (includes 4, so not a solution)
C: 2, 3, 5, 6 (does not include 4, so possible solution)
D: 4, 5, 6, 7 (includes 4, so not a solution)

Therefore, the correct answer is:

C: 2, 3, 5, 6

Answer 2

ok