In trangle abc a=29,b=36,b=15.8cm find a. thank you
4 answers
Please solve.the question
Please check what you typed. You have two sides called b.
since you specify that b=15.8 cm, I assume that you meant angles
A=29° and B=36°
If so, then use the law of sines to get
a/sinA = b/sinB
You need to pay attention to your labels. The triangle is usually named by its angles, in Upper Case.
A=29° and B=36°
If so, then use the law of sines to get
a/sinA = b/sinB
You need to pay attention to your labels. The triangle is usually named by its angles, in Upper Case.
If it is angle A you want and c = 15.8 then
a*2 = 841
b^2 = 1296
c^2 = 249.64
a^2 = b^2 + c^2 - 2 b c cos A (law of cosines)
841 = 1296 + 249.64 - 2 * 36 * 15.8 cos A
a*2 = 841
b^2 = 1296
c^2 = 249.64
a^2 = b^2 + c^2 - 2 b c cos A (law of cosines)
841 = 1296 + 249.64 - 2 * 36 * 15.8 cos A
1 answer