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In this reaction solid NaOH is added to approximately 100 mL of 0.500 mol/L HCl.

Trial 1: 2.02 g of solid NaOH is added to 102.0 mL of the HCl solution. The temperature goes from 22.00°C to 32.0°C.

Calculate the heat evolved in each trial (Q).

I'm confused on how to calculate the heat evolved in the trial. This is what I have so far:
Q = (4.200 kJ/kg oC)(0.1020 kg)(10.00 oC) = 4.284 kJ

1 answer

I don't believe you have posted the entire question; however, what you have is correct so far. Personally, I would have used 4.184 for the specific heat. Most of these questions ask for the heat/mol; you have calculated the heat of the reaction as shown.
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