Pb(ClO3)2(aq) + 2NaI(aq) ==> PbI2(s) + 2NaClO3(aq)
Notice which is the solid ppt. The net ionic equation for PbI2 with the ions leading up to the ppt is Pb^2+(aq) 2I^-(aq) ==> PbI2(s)
The other ions are the spectator ions.
In the reaction between aqueous solutions of lead(II) chlorate and sodium iodide, which ions become spectator ions?
a) Pb2+
b) ClO3-
c) Na+
d) I-
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