If Bx = By, then B = Bxi + Byj + Bzk = Byi + Byj + Bzk = By(i + j + k).
Now, substitute this into the equation F = qv · B:
F = 4(2.0i + 4.0j + 6.0k) · By(i + j + k)
= 8Byi + 16Byj + 24Byk
Now, set this equal to the given F:
136i - 176j + 72k = 8Byi + 16Byj + 24Byk
Solve for By:
By = (136i - 176j + 72k) / (8i + 16j + 24k)
By = 17i - 11j + 3k
Therefore, in unit-vector notation, B = 17i - 11j + 3k.
In the product F = qv · B , take q = 4,
= 2.0i + 4.0j + 6.0k and = 136i -176j + 72k.
What then is in unit-vector notation if Bx = By?
~~may i get some assistance in this problem? so far.. i tried this..
136i-176j+72k = 4(2.0i+4.0j+6.0k)(B)
136i-176j+72k = (8i+16j+24k)(B)
[(136i-176j+72k)/(8i+16j+24k)] = B
17i-11j+3k = B
thats wrong.. so should i be doing this?
136i-176j+72k = (8xi+16yj+24zk)(Bxi+Byj+Bzk)
136i-176j+72k = (8xBxi+16yByj+24zBzk)
???
i need some help asap, that would be great. thanks again!
Fill in the blanks in your question
<< In the product F = qv · B , take q = 4,
___= 2.0i + 4.0j + 6.0k and ___= 136i -176j + 72k.
What then is ___ in unit-vector notation if Bx = By>>
If the B vector is 2.0i + 4.0j + 6.0k, then Bx and By are NOT equal. Your question is incomplete and does not make sense.
You didn't multiply...
136i-176j+72k = (8i+16j+24k)(B)
But B= Bxi +Byj + Bzk
136i-176j+72k = (8i+16j+24k)(Bxi +Byj + Bzk)
136i-176j+72k= 8Bx k -8By j + 16Bx k +16Bz i + 24Bx j- 24By i
Now gather the terms, set the i terms equal to i, and so on. Check my work, I did it in my head.
sorry, the complete question is:
n the product F = qv · B , take q = 4,
v = 2.0i + 4.0j + 6.0k and F= 136i -176j + 72k.
What then is in unit-vector notation if Bx = By?
I still can't get the right answer though...
1 answer