mols KOH = M x L = ?
Look at the equation; it is 1:1, therefore, mols HNO3 = mols KOH.
M HNO3 = mols HNO3/L HNO3.
In the following acid—base neutralization reaction
HNO3(aq)+ KOH(aq) ----KNO3(aq) + H2O (I)
What is the molarity (M) of an HNO3 solution if 50.0 ml is needed to react with 25.0 ml of 0.150M KOH solution?
1 answer
1 answer