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Can someone please explain this problem to me step by step pleaseeeeeee?

In the following acid—base neutralization reaction

HNO3 (aq)+ KOH (aq)---KNO3(aq) + H2O(I)

What is the molarity (M) of an HNO3 solution if 50.0ml is needed to react with 25.0ml of 0.150M KOH solution?

1 answer

How many mols KOH do you have? That's mols KOH = M x L = ?

How many mols HNO3 will that neutralize. The same number since the equation is 1 mol HNO3 to 1 mol KOH.

M HNO3 = mols HNO3/L HNO3.
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