In the figure below Thabo initially at rest throws a ball upward at an angle πœƒπ‘œ with an

initial speed π‘£π‘œ. He tries to catch up to the ball by speeding-up at a constant
acceleration π‘Ž for a time interval βˆ†π‘‘1 and then continues to run at a constant speed for
a time interval βˆ†π‘‘2. He catches the ball at exactly the same height he threw the ball. Let
𝑔 be the gravitational constant. What was Thabo’s acceleration π‘Ž?

2 answers

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I don't see a figures below.