Vo = 15m/s[75o]
Xo = 15*cos75 = 3.88 m/s.
Range = Vo^2*sin(2A)/g
Range = 15^2*sin(150)/9.81 = 11.47 m.
d = 0.5a*t^2 = 11.47 m.
0.5a*1.03^2 = 11.47
0.53a = 11.47
a = 21.6 m/s^2.
A person initially at rest throws a ball upward at an angle θ0= 75 ∘ with an initial speed v0=15 m/s . He tries to catch up to the ball by accelerating with a constant acceleration a for a time interval of 1.03 s and then continues to run at a constant speed for the rest of the trip. He catches the ball at exactly the same height he threw it. Let g= 9.81 m/s2 be the gravitational constant. What was the person's acceleration a (in m/s2)?
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