In the figure, a thin uniform rod of mass m = 3.05 kg and length L = 1.11 m rotates freely about a horizontal axis A that is perpendicular to the rod and passes through a point at a distance d = 0.201 m from the end of the rod. The kinetic energy of the rod as it passes through the vertical position is K = 8.63 J. At what angle £c (in ¢X) will the rod momentarily stop in its upward swing?

Question

In the figure, a thin uniform rod of mass m = 3.05 kg and length L = 1.11 m rotates freely about a horizontal axis A that is perpendicular to the rod and passes through a point at a distance d = 0.201 m from the end of the rod.  The kinetic energy of the rod as it passes through the vertical position is K = 8.63 J.  At what angle £c (in ¢X) will the rod momentarily stop in its upward swing?

I don't really know how to solve the inertia for this one. I got my w value from my r, as L-d and K. Now I was confused is I value.

I calculated my inertia as m(L^2)/12 +m(L-d)^2