An object is formed by attaching a uniform, thin rod with a mass of mr = 6.8 kg and length L = 5.68 m to a uniform sphere with mass ms = 34 kg and radius R = 1.42 m. Note ms = 5mr and L = 4R.
What is the moment of inertia of the object about an axis at the center of mass of the object? (Note: the center of mass can be calculated to be located at a point halfway between the center of the sphere and the left edge of the sphere.)
I have used the formula I = Ir+Is = 1/12MrL^2+Mr(L/2+R/2)^2+13/20MsR^2 and I got 110.5323267
I also used the formula Icm = (MrL^2/12)+Mr(L-(r+(r/2))^2+2/5Msr^2+Ms(r/2)^2 which gave me 238.0776923 but that was also wrong
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