In the diagram of a rhombus ABCD, m angle A = 112 deg What is m<ADB? (1 point

1 answer

In a rhombus, opposite angles are congruent, and adjacent angles are supplementary. Since you have \( m \angle A = 112^\circ \), we can find the measure of angle B:

\[ m \angle B = 180^\circ - m \angle A = 180^\circ - 112^\circ = 68^\circ \]

Now, since the diagonals of a rhombus bisect the angles, \( \angle ADB \) is half of \( \angle A \):

\[ m \angle ADB = \frac{1}{2} m \angle A = \frac{1}{2} \times 112^\circ = 56^\circ \]

Thus, \( m \angle ADB = 56^\circ \).