In the diagram, rhombus ABCD has a diagonal line DB¯¯¯¯¯¯¯¯ , and m∠A=114° . What is m∠B of rhombus ABCD ? (1 point) Responses 57° 57° 33° 33° 114° 114° 66°

1 answer

In a rhombus, opposite angles are equal and the sum of the angles in any quadrilateral is 360°. Since rhombus ABCD has \( m\angle A = 114^\circ \), it follows that \( m\angle C = 114^\circ \) as well (since \( \angle A \) and \( \angle C \) are opposite angles).

Now, to find the measures of angles B and D, we can use the fact that the sum of all angles in a quadrilateral is \( 360^\circ \):

\[ m\angle A + m\angle B + m\angle C + m\angle D = 360^\circ \]

Substituting the known values:

\[ 114^\circ + m\angle B + 114^\circ + m\angle D = 360^\circ \]

This simplifies to:

\[ 228^\circ + m\angle B + m\angle D = 360^\circ \]

Now, simplify further to find:

\[ m\angle B + m\angle D = 360^\circ - 228^\circ \] \[ m\angle B + m\angle D = 132^\circ \]

Since \( m\angle B \) and \( m\angle D \) are also equal (opposite angles in a rhombus):

\[ m\angle B = m\angle D \]

We can substitute \( m\angle D \) with \( m\angle B \):

\[ m\angle B + m\angle B = 132^\circ \] \[ 2m\angle B = 132^\circ \]

Dividing both sides by 2:

\[ m\angle B = 66^\circ \]

Thus, the measure of angle B in rhombus ABCD is \( \boxed{66^\circ} \).