In the Bohr model of the hydrogen atom, an electon mass= 9.11 x 10^-31 kg orbits a proton at a radius of 5.29 x 10^-11 m. The proton pulls on the electron with a force of 8.20 x 10^-8N. what is the speed of the electron? what is the period of the electron?
I really need help setting this up.
2 answers
F = m v^2/r
does this look right...
mg + force of proton = mv^2/r
9.8m/s2 + 8.20 x 10^-8n = v^2/r
8.20 x 10^-8 (5.29 x 10^-11) = v^2
4.34 x 10^-18 = v^2
v= 2.08 x 10^-9
this is for the speed
mg + force of proton = mv^2/r
9.8m/s2 + 8.20 x 10^-8n = v^2/r
8.20 x 10^-8 (5.29 x 10^-11) = v^2
4.34 x 10^-18 = v^2
v= 2.08 x 10^-9
this is for the speed
1 answer