you know that the area is
(AB*BC)/2 = (√34*BC)/2=17
BC = 34/√34 = √34
So, now you know that
5^2 + (2-y)^2 = 34
y = 5 or -1
In right angled triangle ABC,angle B=90degree and AB=√34unit.The coordinates of points B,C are(4,2)&(-1,y).if ar(ABC)=17units then find the value of y
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