area = (1/2)(BC)(AB)
17 = (1/2)(√(5^2 + (2-y)^2 ) (√34
34/√34 = √(25 + 4 - 4y + y^2)
square both sides
34 = 29 - 4y + y^2
y^2 - 4y - 5 = 0
(y-5)(y+1) = 0
y = 5 or y = -1
In right angled triangle ABC angle B=90 degree
and AB= root 34 unit. The coordinates of point B and Care (4,2)and (-1,y) respectively.
If area of triangle ABC = 17 sq.units, then find value of y.
4 answers
this answer sux
Pawar Ka jabdaa
This is not a perfect answer I think so..